3.3.72 \(\int \frac {x^3 (c+d x^2)^2}{(a+b x^2)^2} \, dx\)

Optimal. Leaf size=88 \[ \frac {a (b c-a d)^2}{2 b^4 \left (a+b x^2\right )}+\frac {(b c-3 a d) (b c-a d) \log \left (a+b x^2\right )}{2 b^4}+\frac {d x^2 (b c-a d)}{b^3}+\frac {d^2 x^4}{4 b^2} \]

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Rubi [A]  time = 0.11, antiderivative size = 88, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 22, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.091, Rules used = {446, 77} \begin {gather*} \frac {d x^2 (b c-a d)}{b^3}+\frac {a (b c-a d)^2}{2 b^4 \left (a+b x^2\right )}+\frac {(b c-3 a d) (b c-a d) \log \left (a+b x^2\right )}{2 b^4}+\frac {d^2 x^4}{4 b^2} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(x^3*(c + d*x^2)^2)/(a + b*x^2)^2,x]

[Out]

(d*(b*c - a*d)*x^2)/b^3 + (d^2*x^4)/(4*b^2) + (a*(b*c - a*d)^2)/(2*b^4*(a + b*x^2)) + ((b*c - 3*a*d)*(b*c - a*
d)*Log[a + b*x^2])/(2*b^4)

Rule 77

Int[((a_.) + (b_.)*(x_))*((c_) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Int[ExpandIntegran
d[(a + b*x)*(c + d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, n}, x] && NeQ[b*c - a*d, 0] && ((ILtQ[
n, 0] && ILtQ[p, 0]) || EqQ[p, 1] || (IGtQ[p, 0] && ( !IntegerQ[n] || LeQ[9*p + 5*(n + 2), 0] || GeQ[n + p + 1
, 0] || (GeQ[n + p + 2, 0] && RationalQ[a, b, c, d, e, f]))))

Rule 446

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_.)*((c_) + (d_.)*(x_)^(n_))^(q_.), x_Symbol] :> Dist[1/n, Subst[Int
[x^(Simplify[(m + 1)/n] - 1)*(a + b*x)^p*(c + d*x)^q, x], x, x^n], x] /; FreeQ[{a, b, c, d, m, n, p, q}, x] &&
NeQ[b*c - a*d, 0] && IntegerQ[Simplify[(m + 1)/n]]

Rubi steps

\begin {align*} \int \frac {x^3 \left (c+d x^2\right )^2}{\left (a+b x^2\right )^2} \, dx &=\frac {1}{2} \operatorname {Subst}\left (\int \frac {x (c+d x)^2}{(a+b x)^2} \, dx,x,x^2\right )\\ &=\frac {1}{2} \operatorname {Subst}\left (\int \left (\frac {2 d (b c-a d)}{b^3}+\frac {d^2 x}{b^2}-\frac {a (-b c+a d)^2}{b^3 (a+b x)^2}+\frac {(b c-3 a d) (b c-a d)}{b^3 (a+b x)}\right ) \, dx,x,x^2\right )\\ &=\frac {d (b c-a d) x^2}{b^3}+\frac {d^2 x^4}{4 b^2}+\frac {a (b c-a d)^2}{2 b^4 \left (a+b x^2\right )}+\frac {(b c-3 a d) (b c-a d) \log \left (a+b x^2\right )}{2 b^4}\\ \end {align*}

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Mathematica [A]  time = 0.06, size = 87, normalized size = 0.99 \begin {gather*} \frac {2 \left (3 a^2 d^2-4 a b c d+b^2 c^2\right ) \log \left (a+b x^2\right )+4 b d x^2 (b c-a d)+\frac {2 a (b c-a d)^2}{a+b x^2}+b^2 d^2 x^4}{4 b^4} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(x^3*(c + d*x^2)^2)/(a + b*x^2)^2,x]

[Out]

(4*b*d*(b*c - a*d)*x^2 + b^2*d^2*x^4 + (2*a*(b*c - a*d)^2)/(a + b*x^2) + 2*(b^2*c^2 - 4*a*b*c*d + 3*a^2*d^2)*L
og[a + b*x^2])/(4*b^4)

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IntegrateAlgebraic [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {x^3 \left (c+d x^2\right )^2}{\left (a+b x^2\right )^2} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

IntegrateAlgebraic[(x^3*(c + d*x^2)^2)/(a + b*x^2)^2,x]

[Out]

IntegrateAlgebraic[(x^3*(c + d*x^2)^2)/(a + b*x^2)^2, x]

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fricas [A]  time = 1.00, size = 160, normalized size = 1.82 \begin {gather*} \frac {b^{3} d^{2} x^{6} + 2 \, a b^{2} c^{2} - 4 \, a^{2} b c d + 2 \, a^{3} d^{2} + {\left (4 \, b^{3} c d - 3 \, a b^{2} d^{2}\right )} x^{4} + 4 \, {\left (a b^{2} c d - a^{2} b d^{2}\right )} x^{2} + 2 \, {\left (a b^{2} c^{2} - 4 \, a^{2} b c d + 3 \, a^{3} d^{2} + {\left (b^{3} c^{2} - 4 \, a b^{2} c d + 3 \, a^{2} b d^{2}\right )} x^{2}\right )} \log \left (b x^{2} + a\right )}{4 \, {\left (b^{5} x^{2} + a b^{4}\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3*(d*x^2+c)^2/(b*x^2+a)^2,x, algorithm="fricas")

[Out]

1/4*(b^3*d^2*x^6 + 2*a*b^2*c^2 - 4*a^2*b*c*d + 2*a^3*d^2 + (4*b^3*c*d - 3*a*b^2*d^2)*x^4 + 4*(a*b^2*c*d - a^2*
b*d^2)*x^2 + 2*(a*b^2*c^2 - 4*a^2*b*c*d + 3*a^3*d^2 + (b^3*c^2 - 4*a*b^2*c*d + 3*a^2*b*d^2)*x^2)*log(b*x^2 + a
))/(b^5*x^2 + a*b^4)

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giac [A]  time = 0.28, size = 163, normalized size = 1.85 \begin {gather*} \frac {\frac {{\left (b x^{2} + a\right )}^{2} {\left (d^{2} + \frac {2 \, {\left (2 \, b^{2} c d - 3 \, a b d^{2}\right )}}{{\left (b x^{2} + a\right )} b}\right )}}{b^{3}} - \frac {2 \, {\left (b^{2} c^{2} - 4 \, a b c d + 3 \, a^{2} d^{2}\right )} \log \left (\frac {{\left | b x^{2} + a \right |}}{{\left (b x^{2} + a\right )}^{2} {\left | b \right |}}\right )}{b^{3}} + \frac {2 \, {\left (\frac {a b^{4} c^{2}}{b x^{2} + a} - \frac {2 \, a^{2} b^{3} c d}{b x^{2} + a} + \frac {a^{3} b^{2} d^{2}}{b x^{2} + a}\right )}}{b^{5}}}{4 \, b} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3*(d*x^2+c)^2/(b*x^2+a)^2,x, algorithm="giac")

[Out]

1/4*((b*x^2 + a)^2*(d^2 + 2*(2*b^2*c*d - 3*a*b*d^2)/((b*x^2 + a)*b))/b^3 - 2*(b^2*c^2 - 4*a*b*c*d + 3*a^2*d^2)
*log(abs(b*x^2 + a)/((b*x^2 + a)^2*abs(b)))/b^3 + 2*(a*b^4*c^2/(b*x^2 + a) - 2*a^2*b^3*c*d/(b*x^2 + a) + a^3*b
^2*d^2/(b*x^2 + a))/b^5)/b

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maple [A]  time = 0.01, size = 142, normalized size = 1.61 \begin {gather*} \frac {d^{2} x^{4}}{4 b^{2}}-\frac {a \,d^{2} x^{2}}{b^{3}}+\frac {c d \,x^{2}}{b^{2}}+\frac {a^{3} d^{2}}{2 \left (b \,x^{2}+a \right ) b^{4}}-\frac {a^{2} c d}{\left (b \,x^{2}+a \right ) b^{3}}+\frac {3 a^{2} d^{2} \ln \left (b \,x^{2}+a \right )}{2 b^{4}}+\frac {a \,c^{2}}{2 \left (b \,x^{2}+a \right ) b^{2}}-\frac {2 a c d \ln \left (b \,x^{2}+a \right )}{b^{3}}+\frac {c^{2} \ln \left (b \,x^{2}+a \right )}{2 b^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^3*(d*x^2+c)^2/(b*x^2+a)^2,x)

[Out]

1/4*d^2*x^4/b^2-d^2/b^3*a*x^2+d/b^2*c*x^2+1/2/b^4*a^3/(b*x^2+a)*d^2-1/b^3*a^2/(b*x^2+a)*d*c+1/2/b^2*a/(b*x^2+a
)*c^2+3/2/b^4*ln(b*x^2+a)*a^2*d^2-2/b^3*ln(b*x^2+a)*a*d*c+1/2/b^2*ln(b*x^2+a)*c^2

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maxima [A]  time = 1.00, size = 107, normalized size = 1.22 \begin {gather*} \frac {a b^{2} c^{2} - 2 \, a^{2} b c d + a^{3} d^{2}}{2 \, {\left (b^{5} x^{2} + a b^{4}\right )}} + \frac {b d^{2} x^{4} + 4 \, {\left (b c d - a d^{2}\right )} x^{2}}{4 \, b^{3}} + \frac {{\left (b^{2} c^{2} - 4 \, a b c d + 3 \, a^{2} d^{2}\right )} \log \left (b x^{2} + a\right )}{2 \, b^{4}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^3*(d*x^2+c)^2/(b*x^2+a)^2,x, algorithm="maxima")

[Out]

1/2*(a*b^2*c^2 - 2*a^2*b*c*d + a^3*d^2)/(b^5*x^2 + a*b^4) + 1/4*(b*d^2*x^4 + 4*(b*c*d - a*d^2)*x^2)/b^3 + 1/2*
(b^2*c^2 - 4*a*b*c*d + 3*a^2*d^2)*log(b*x^2 + a)/b^4

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mupad [B]  time = 0.07, size = 112, normalized size = 1.27 \begin {gather*} \frac {a^3\,d^2-2\,a^2\,b\,c\,d+a\,b^2\,c^2}{2\,b\,\left (b^4\,x^2+a\,b^3\right )}-x^2\,\left (\frac {a\,d^2}{b^3}-\frac {c\,d}{b^2}\right )+\frac {d^2\,x^4}{4\,b^2}+\frac {\ln \left (b\,x^2+a\right )\,\left (3\,a^2\,d^2-4\,a\,b\,c\,d+b^2\,c^2\right )}{2\,b^4} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((x^3*(c + d*x^2)^2)/(a + b*x^2)^2,x)

[Out]

(a^3*d^2 + a*b^2*c^2 - 2*a^2*b*c*d)/(2*b*(a*b^3 + b^4*x^2)) - x^2*((a*d^2)/b^3 - (c*d)/b^2) + (d^2*x^4)/(4*b^2
) + (log(a + b*x^2)*(3*a^2*d^2 + b^2*c^2 - 4*a*b*c*d))/(2*b^4)

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sympy [A]  time = 0.93, size = 99, normalized size = 1.12 \begin {gather*} x^{2} \left (- \frac {a d^{2}}{b^{3}} + \frac {c d}{b^{2}}\right ) + \frac {a^{3} d^{2} - 2 a^{2} b c d + a b^{2} c^{2}}{2 a b^{4} + 2 b^{5} x^{2}} + \frac {d^{2} x^{4}}{4 b^{2}} + \frac {\left (a d - b c\right ) \left (3 a d - b c\right ) \log {\left (a + b x^{2} \right )}}{2 b^{4}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**3*(d*x**2+c)**2/(b*x**2+a)**2,x)

[Out]

x**2*(-a*d**2/b**3 + c*d/b**2) + (a**3*d**2 - 2*a**2*b*c*d + a*b**2*c**2)/(2*a*b**4 + 2*b**5*x**2) + d**2*x**4
/(4*b**2) + (a*d - b*c)*(3*a*d - b*c)*log(a + b*x**2)/(2*b**4)

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